if m is the middle point of xy and m(-3,1) and y(-8,6) what is x

The coordinates of the midpoint \( M \) of the line segment connecting two points \( X(x_1, y_1) \) and \( Y(x_2, y_2) \) can be found using the midpoint formula: \[ M = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) \] In this case, we know: - The midpoint \( M \) is given as \( (-3, 1) \). - The coordinates of point \( Y \) are given as \( Y(-8, 6) \). Let the coordinates of point \( X \) be \( X(x, y) \). According to the midpoint formula, we can set up the following equations: \[ \frac{x + (-8)}{2} = -3 \] \[ \frac{y + 6}{2} = 1 \] Now, we will solve for \( x \) and \( y \). Starting with the first equation: \[ \frac{x - 8}{2} = -3 \] Multiplying both sides by 2: \[ x - 8 = -6 \] Adding 8 to both sides: \[ x = 2 \] Now for the second equation: \[ \frac{y + 6}{2} = 1 \] Multiplying both sides by 2: \[ y + 6 = 2 \] Subtracting 6 from both sides: \[ y = -4 \] Thus, the coordinates of point \( X \) are \( (2, -4) \). Therefore, the value of \( x \) is: \[ \boxed{2} \]