if sk=13x-5 Ky=2x+9 and SY=36-x find x

To find the value of \( x \), we first need to clarify the relationships among the variables given in your equations. It seems that \( S \), \( K \), and \( Y \) refer to some geometrical figures or segments. Generally, the equations could represent segments in a triangle or some other configuration. You provided these equations: 1. \( SK = 13x - 5 \) 2. \( KY = 2x + 9 \) 3. \( SY = 36 - x \) Assuming that these lengths are related such that: \[ SK + KY = SY \] we can set up the following equation: \[ (13x - 5) + (2x + 9) = 36 - x \] Now, let's simplify and solve for \( x \): 1. Combine the terms on the left side: \[ 13x - 5 + 2x + 9 = 36 - x \] \[ 15x + 4 = 36 - x \] 2. Add \( x \) to both sides: \[ 15x + x + 4 = 36 \] \[ 16x + 4 = 36 \] 3. Subtract 4 from both sides: \[ 16x = 32 \] 4. Divide both sides by 16: \[ x = 2 \] Thus, the value of \( x \) is \( \boxed{2} \).