Max and his friend push horizontally on a 40 kg crate with a force of 500 N. The friction force between the floor and the crate is 260 N. What is the acceleration of the crate?

To find the acceleration of the crate, we first need to determine the net force acting on it. The forces acting on the crate can be summarized as follows: 1. Applied force (F_applied): 500 N (the force Max and his friend exert) 2. Friction force (F_friction): 260 N (the force opposing the applied force) The net force (F_net) can be calculated using the formula: \[ F_{\text{net}} = F_{\text{applied}} - F_{\text{friction}} \] Substituting in the values we have: \[ F_{\text{net}} = 500 \, \text{N} - 260 \, \text{N} = 240 \, \text{N} \] Next, we can use Newton's second law of motion to find the acceleration of the crate. Newton's second law states that: \[ F_{\text{net}} = m \cdot a \] Where: - \( F_{\text{net}} \) is the net force - \( m \) is the mass of the crate - \( a \) is the acceleration Given the mass of the crate is 40 kg, we can rearrange the equation to solve for acceleration \( a \): \[ a = \frac{F_{\text{net}}}{m} \] Now substituting in the values we calculated: \[ a = \frac{240 \, \text{N}}{40 \, \text{kg}} = 6 \, \text{m/s}^2 \] Therefore, the acceleration of the crate is: \[ \boxed{6 \, \text{m/s}^2} \]